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LekaFEV [45]
3 years ago
11

[(-3)+9] × [(-10)-(-9)]please solve this​

Mathematics
1 answer:
exis [7]3 years ago
8 0
[(-3)+9] × [(-10)-(-9)]

6 × (-10 + 9)

6 × (-1)

= -6
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For this case we have the following variables:
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An expressions that gives the total amount, in dollars, collected for weekly fees last year is:
 
20v + 10p
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How many 1/4 are in 5?
mina [271]
Do 4x5, that is all you need to do, did you learn fractions in elementary?
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A random sample of 18 adults, chosen from the 1500 adults in the town, took a survey asking their opinion on a recent property t
Tamiku [17]

Answer:

C) I & III

Step-by-step explanation:

Given:

Sample size, n = 18

Sample proportion = 25% = 0.25

Here, a random sample of 18 adults were chosen from the 1500 adults in town. This shows that the random condition was satisfied because the sample was drawn randomly from the general population of adults in the town.

For the normal condition to be satisfied, np should be greater than 10, ie np > 10.

In this case, np = 18 * 0.25 = 4.5

Since np is less than 10, the normal condition was not satisfied.

For the 10% condition to be satisfied, sample size should not be more than 10% of the general population.

Here, the sample size is 18 and the population is 1500. Therefore,

\frac{18}{1500} * 100 = 1.2

Since the sample size is 1.2% of the population which is less than 10%, the 10% condition was satisfied.

The correct option is C, because only I & III were satisfied.

4 0
3 years ago
ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (
harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

<em>See the image in the attachment for the referred diagram.</em>

<em />

  • The two triangles, triangle AEC and triangle BDC are similar triangles.
  • Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

  • AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

  • Plug in the values

\frac{8.1}{5.4} = \frac{AE}{2.6}

  • Cross multiply

5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06

  • Divide both sides by 5.4

AE = \frac{21.06}{5.4} = 3.9 $ cm

<u>b. </u><u>Find the length of </u><u>AB:</u>

AB = AC - BC

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

  • Plug in the values

\frac{6.15}{BC} = \frac{8.1}{5.4}

  • Cross multiply

BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1

  • Thus:

AB = AC - BC

  • Substitute

AB = 6.15 - 4.1\\\\AB = 2.05 $ cm

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

Learn more here:

brainly.com/question/14327552

3 0
3 years ago
(x³ + ³) / (x - y)<br> Do not include parentheses in your answer.
Lubov Fominskaja [6]

The simplified expression of \frac{x^3 + (-y)^3}{(x - y} is x^2+xy+y^2

<h3>Complete question</h3>

Simplify the expression: (x³ + (-y)³) / (x - y)

Do not include parentheses in your answer.

<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x^3 + (-y)^3}{(x - y}

Open the inner bracket

\frac{x^3 -y^3}{(x - y}

Apply the difference of two cubes to the numerator

\frac{(x-y)(x^2+xy+y^2)}{(x - y}


Cancel out the common factors

x^2+xy+y^2

Hence, the simplified expression of \frac{x^3 + (-y)^3}{(x - y} is x^2+xy+y^2

Read more about expressions at:

brainly.com/question/723406

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4 0
2 years ago
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