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shtirl [24]
2 years ago
9

A triangle has vertices at (3,2),(3,6),(7,2) find the area of the triangle

Mathematics
1 answer:
yawa3891 [41]2 years ago
7 0

Answer:

  8 square units

Step-by-step explanation:

The base is on a horizontal line. The points are 7-3 = 4 units apart.

The side perpendicular to the base is a vertical segment 6 -2 = 4 units long.

The area is ...

  A = 1/2bh

  A = 1/2(4 units)(4 units) = 8 units²

The area of the triangle is 8 square units.

__

It is effectively half of a square that is 4 units on a side. 1/2(4²) = 8.

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For the inverse variation equation p = StartFraction 8 Over V EndFraction, what is the value of V when p = one-half?
likoan [24]

Answer:

V=16

Step-by-step explanation:

We are given that an inverse variation

p=\frac{8}{V}

We have to find the value of V when p=1/2

To find the value of V we will substitute the value of p

Substitute the value of p

Then, we get

\frac{1}{2}=\frac{8}{V}

\frac{V}{2}=8

Using multiplication property of equality

V=8\times 2

Using multiplication property of equality

V=16

Hence, the value of V=16

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3 years ago
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Question 2 <br><br> help pls its hard i forgt how to do it
Arada [10]

Answer: 52

Step-by-step explanation:

a^2+b^2=c^2

x is the hypotenuse (c). You can find the hypotenuse by finding the opposite of the right angle

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1 year ago
Estimate then record the product 293*4
jolli1 [7]

I believe that the equations answer is around 1170. The answer to the equation is 1172

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4 years ago
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