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3 years ago

What is the value of x? The correct answer is 4 but how would I solve this?

Mathematics

1 answer:

Furkat [3]3 years ago

5 0

Answer: 4

Step-by-step explanation: Using Sine, Cosine, and Tangent, you use 8 as the hypotenuse and put your 60 w/ you Cos, so it will read cos60*=adj/8. Then you'll multiply both sides by 8, so it will be 8*cos60=adj. So, the cosine of 60 is 1/2, you multiply that by 8, then that equals 4, I hope that helps!

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Pleass HELP I GIVE BRILLIANT ANSWER

shusha [124]

Answer:

The Best answer will be D having to add 7 then subtracting 8, becoming -1, then dividing to become D.

Step-by-step explanation:

6 0

3 years ago

If f(x)=2x+5x and g(x)=3x-5,find (f+g)(x)

kati45 [8]

The answer is $(f+g)(x)=10x-5$

Step-by-step explanation:

Given that $f(x)=2x+5x$ and $g(x)=3x-5$

To find : $(f+g)(x)$

Now, assign the value $g(x)=3x-5$ in $(f+g)(x)$

$(f+g)(x)=(f+3x-5)$

Also, assign the value $f(x)=2x+5x$ in $(f+g)(x)$

$(f+g)(x)=(2x+5x+3x-5)$

Now, adding the like terms , we get,

$(f+g)(x)=10x-5$

Thus, the value of $(f+g)(x)$ is $(f+g)(x)=10x-5$

3 0

4 years ago

Read 2 more answers

Find the area of the figure.

seraphim [82]

$\huge \bf༆ Answer ༄$

At first Divide the figure into two rectangles, I and Il

Area of figure l is ~

$\sf24 \times (40 - 30)$

$\sf24 \times 10$

$\sf240 \: \: ft {}^{2}$

Area of figure ll is ~

$\sf 18 \times 30$

$\sf540 \: ft{}^{2}$

Area of whole figure = Area ( l + ll )

that is equal to ~

$\sf240 + 540$

$\sf780 \: \: ft{}^{2}$

7 0

2 years ago

The random variable x represents the number of dogs per household in a town with 1,000 households. Find the probability of rando

Elan Coil [88]

Answer:

0.35

Step-by-step explanation:

P(0) = 348/1000

0.348

0.35 to the nearest hundredth

8 0

3 years ago

The College Board originally scaled SAT scores so that the scores for each section were approximately normally distributed with

likoan [24]

Answer:

Percentage of students who scored greater than 700 = 97.72%

Step-by-step explanation:

We are given that the College Board originally scaled SAT scores so that the scores for each section were approximately normally distributed with a mean of 500 and a standard deviation of 100.

Let X = percentage of students who scored greater than 700.

Since, X ~ N( $\mu, \sigma^{2}$ )

The z probability is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1) where, $\mu$ = 500 and $\sigma$ = 100

So, P(percentage of students who scored greater than 700) = P(X > 700)

P(X > 700) = P( $\frac{X-\mu}{\sigma}$ < $\frac{700-500}{100}$ ) = P(Z < 2) = 0.97725 or 97.72% Therefore, percentage of students who scored greater than 700 is 97.72%.

8 0

3 years ago