Answer:
Radius=2.09 cm
Height,h=14.57 cm
Step-by-step explanation:
We are given that
Volume of cylinderical shaped can=200 cubic cm.
Cost of sides of can=0.02 cents per square cm
Cost of top and bottom of the can =0.07 cents per square cm
Curved surface area of cylinder=
Area of circular base=Area of circular top=
Total cost,C(r)=
Volume of cylinder,


Substitute the value of h


Differentiate w.r.t r






Again, differentiate w.r.t r

Substitute the value of r

Therefore,the product cost is minimum at r=2.09
h=
Radius of can,r=2.09 cm
Height of cone,h=14.57 cm
Answer:
3.16 units
Step-by-step explanation:
It has been given that the triangles JKL and the triangle RST are congruent.
That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.
Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are
and
.
The length of the side RS is equal to the distance between point R and S.
RS 



Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.
Negative exponents mean that the base is on the wrong side of the fraction line. For example, x^-2 is the same as 1/x^2. In this example, 1/2^-2 would be 2.
2/1^2 = 2
Answer:
x = 6
Step-by-step explanation:
8x = 48,
Divide each side by 8 to isolate x
8x/8 = 48/8
x = 6