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2 years ago

A group of students surveyed chose baseball and soccer as their favorite sport in the ratio 3:8

1 answer:

5 0

$3x-\ those\ who\ chose\ baseball\\8x-\ those\ who\ chose\ soccer\\\\
a)\\3x+8x=132\\\\
11x=132\ \ \ | divide\ by\ 11\\\\x=12\\\\
8x=8*12=96\\\\
96\ chose\ soccer.\\\\\
b)\\8x=56\ \ \ | divide\ by\ 8\\\\x=7\\\\
3x=3*7=21\\\\
21\ chose\ baseball.$

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I need help with the Algebra functions and data question

Sunny_sXe [5.5K]

C is the correct answer !!

4 0

3 years ago

Read 2 more answers

Joel built a model town. He constructed three buildings that each had a volume of 18 cm cubed. Each building looked different. W

morpeh [17]

Answer:

The three buildings can look like following:

1. The building can look like a cube, with each side and height equal to 2.62 cm.

2. The building can look like a cuboid, with 3 cm length, 1 cm breadth and 6 cm height.

3. The building can look like a pyramid, with 3 cm length, 3 cm breadth and 6 cm height.

Step-by-step explanation:

The three possibilities of the appearance or shape of the building, with the volume equal to 18 cm³ are as follows:

1. CUBIC SHAPE:

The building can look like a cube with the length of each side and height given as:

Volume of Cube = 18 cm³ = L³

L = ∛18 cm³ = 2.62 cm

Thus, the building can look like a cube, with each side and height equal to 2.62 cm.

2. CUBOID SHAPE:

The building can also look like cuboid with the following dimensions.

Length = 3 cm

Breadth = 1 cm

Height = 6 cm

Thus, the volume becomes:

Volume of Cuboid = Length * Breadth * Height

Volume of Cuboid = 3 cm * 1 cm * 6 cm = 18 cm³

Thus, the building can look like a cuboid, with 3 cm length, 1 cm breadth and 6 cm height.

3. PYRAMID SHAPE:

The building can also look like pyramid with the following dimensions.

Length = 3 cm

Breadth = 3 cm

Height = 6 cm

Thus, the volume becomes:

Volume of Pyramid = (Length * Breadth * Height)/3

Volume of Cuboid = (3 cm * 3 cm * 6 cm)/3 = 18 cm³

Thus, the building can look like a pyramid, with 3 cm length, 3 cm breadth and 6 cm height.

5 0

3 years ago

A bucket that weighs 4lband a rope of negligible weight are used todraw water from a well that is 80ftdeep. The bucket is filled

liq [111]

Answer:

Workdone = 3200 lb.ft

Step-by-step explanation:

We are told that the bucket is filled with 40 lb of water but water leaks out of a hole in the bucket at a rate of 0.2lb/s

Thus,

Weight of water at any given time (t) would be;

w(t) = 40 - 0.2t - - - - (1)

We are told the bucket is pulled up at a rate of 2ft/s.

Thus, height at time (t); y = 0 + 2t = 2t

Since y = 2t,

Then,t = y/2

Put y/2 for t in eq 1

Thus; w(y) = 40 - 0.2(y/2)

w(y) = 40 - 0.1y

Now, at y = 80 ft, we have;

w(80) = 40 - 0.1(80)

w(80) = 40 - 8 = 32 lb

Since 32 lbs are left, it means there is always water in the bucket.

Thus, work done is;

W = 80,0[∫(Total weight).dy]

W = 80,0[∫[(weight of rope) + (weight of bucket) + (weight of water)]dy]

W = 80,0[∫[0 + 4 + 40 - 0.1y]dy]

Integrating, we have;

W = [44y - y²/20] at boundary of 80 and 0

So,

W = [44(80) - 80²/20] - [0 - 0²/20]

W = 3200 lb.ft

8 0

2 years ago

Simplify the square root of 32/5

elixir [45]

Remember $\sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} }$
and
$\sqrt{ab^2} =b \sqrt{a}$
$\sqrt{ \frac{32}{5} } = \frac{ \sqrt{(4^2)(2)} }{ \sqrt{5} } = \frac{ 4\sqrt{2} }{ \sqrt{5} }$
times whoe thing by $\frac{ \sqrt{5} }{ \sqrt{5} }$
$\frac{4 \sqrt{10} }{5}$

3 0

2 years ago

1. Solve: 6x - 12 < 6 2. Solve: 2(3x-8) >8

8090 [49]

Answer:

Step-by-step explanation:

1. here you go mate

step 1

6x - 12 < 6 equation

step 2

6x - 12 < 6 simplify

6x-12+12<6+12

step 3

6x<18 Divide both sides

$\frac{6x}{6}$

answer

x<3

2. Here you go mate

step 1

2(3x-8) >8 equation

step 2

2(3x-8) >8 simplify

6x-16+16>8+16

step 3

6x>24 divide both sides

$\frac{6x}{6} >\frac{24}{6}$

answer

x>4

4 0

3 years ago