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juin [17]
3 years ago
9

18 first-graders and 72 other students attended a school assembly. What percentage of the students at the assembly were first-gr

aders?
Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Answer:20%

Step-by-step explanation:

You add 72 plus 18 and get 100 then you find what 100 divided by 5 is.

Bumek [7]3 years ago
4 0

Answer:

20%

Step-by-step explanation:

72+18=90

18/90=.2

20%

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Your answer is $19.26

Step-by-step explanation:

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Here is the method for solving that equation:

Step #1:  Write the equation:

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3 years ago
what is the price per cubic inch for the extra large tub of popcorn(That costs $9.99) that has a volume of 785.4
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6 0
3 years ago
3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are
natta225 [31]

Using the binomial distribution, the probabilities are given as follows:

a) 0.4159 = 41.59%.

b) 0.5610 = 56.10%.

c) 0.8549 = 85.49%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

n = 3, p = 0.76.

Item a:

The probability is P(X = 2), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159

Item b:

The probability is P(X < 3), hence:

P(X < 3) = 1 - P(X = 3)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390

Then:

P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.

Item c:

The probability is:

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
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