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MatroZZZ [7]
4 years ago
6

Please help me this is a test

Mathematics
1 answer:
Pepsi [2]4 years ago
8 0

Answer:

B. 2

Step-by-step explanation:

For x = 2, w(x) = 3, t(x) = - 1

w(x) + t(x) = 3 + (-1) = 3 - 1 = 2

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Simplify each write as a smaller fractions or mixed number 6 / 18
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6/18= 1/3 a simplest fraction
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Warren wants to build a rectangular enclosure for his animals. one side of the pen will be against the barn, so he needs no fenc
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L +2w = 500
a = lw

a) l = 500 -2w
.. a = (500 -2w)*w


b) The zeros of the above equation are w=0, w=250. The vertex of this quadratic is on the line of symmetry, halftway between the zeros, at w=125 ft.


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3 years ago
You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a
Karo-lina-s [1.5K]

Answer:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967      

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

\bar X=573 represent the sample mean

\mu population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=36-1=35

The Confidence level is 0.90 or 90%, the significance would be \alpha=0.1 and \alpha/2 =0.05, and the critical value for this case would be t_{\alpha/2}=1.690

And replacing we got:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967    

And the 90% confidence interval would be between [566.8033 and 579.1967]

6 0
4 years ago
= 272 and
BlackZzzverrR [31]
D) attached is a picture, I would’ve typed it out but I can’t use the square root symbol

5 0
3 years ago
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