X^2+7x+12/x+3
x^2+7x+12/x+3
x^3+7x^2+12+3x/x
x^3+7x^2+3x+12/x
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Let rs.5 denominations be x , then rs 10 denominations will be 90-x
then total amount 5x + 10(90-x) which is rs.500
5x + 10(90-x) = 500
900 - 5x = 500
400 = 5x
therefore x = 80
therefore no. of rs.5 is 80
no. of rs.10 is 90-x = 90-80 = 10
Answer:
a = 2, b = 3.5
Step-by-step explanation:
Expanding
using Binomial expansion, we have that:
=


We have that the coefficients of the first two terms are 128 and -224.
For the first term:
=>
=> ![a = \sqrt[7]{128}\\ \\\\a = 2](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B7%5D%7B128%7D%5C%5C%20%5C%5C%5C%5Ca%20%3D%202)
For the second term:

Therefore, a = 2, b = 3.5
Step-by-step explanation:
Y is directly proportional to X" can be rewritten as a mathematical expression of the form Y = KX
"K" is the constant of proportionality and must be determined from the initial information.
If Y = 2/3 when X=1/12means 2/3=1/12
K = 2/3÷1/12 = 8
Now that we know the value of K, we can use it to calculate the value of Y when X=1/2
Y = (8)(1/2) = 8/2=4
Y=4