4 years ago

Need help ^^^^^^^^^^

1 answer:

4 0

The answer is B. 2y+3
this is proven by multiplying the divisor of the original question and the solution
$(y-5)(2y+3)
 2y^{2}+3y-10y-15
 2y^{2}-7y-15$

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Bumek [7]

Answer:

Step-by-step explanation:

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3 years ago

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scoray [572]

Answer:

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3 years ago

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Simplify the expression. 10C7 A. 1 B. 3,628,800 C. 604,800 D. 120

Sophie [7]

Answer:

Combination

Step-by-step explanation:

Here by 10C7 we actually mean, $C_{7}^{10}$

And the formula for evaluating mCn is

$=\frac{m!}{n!*(m-n)!}$

Therefore

10C7 =

$=\frac{10!}{7!*(10-7)!} \\=\frac{10!}{7!*3!} \\$

Where m! is called m factorial and can be evaluated as

m!= m*(m-1)*(m-2)*(m-3)*.......3*2*1

Hence

10!= 10*9*8......*3*2*1

7!= 7*8*6.....3*2*1

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With these we can evaluate

10C7

$=\frac{10*9*8*7*.....3*2*1}{(3*2*1)*(7*6*5....3*2*1)}\\=\frac{10*9*8}{3*2*1} \\=\frac{10*3*4}{1} \\=120$

Hence the answer is D

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3 years ago