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2 years ago

A hubcap has a radius of 40in. What is the area of the hubcap

Mathematics

1 answer:

stich3 [128]2 years ago

8 0

Answer:

5,024 inches squared

Step-by-step explanation:

Since the area of a circle is pi r^2, we basically have to replace the r with 40, since it's the radius. Therefore when replaced, it would be pi(40)^2. This makes 1600pi. Pi is technically 3.14, so I multiplied 3.14 and 1600 to get 5,024 inches squared.

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jeka57 [31]

Answer:

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2 years ago

Find the sum of 89 and - 75

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Step-by-step explanation:

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1 year ago

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Answer:

Step-by-step explanation:

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1 year ago

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2 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

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2 years ago