Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
Answer:
$6.66 and $7.04
Please give me brainliest, I really need it.
It’s 500.07
all i did was solve x-7%=500 and got 500.07.
9514 1404 393
Answer:
![\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-2%5C%5C0%26-3%265%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The rotation matrix for 90° CCW is ...
![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Then the rotated coordinates are ...
![\left[\begin{array}{ccc}0&-1\\1&0\end{array}\right]\cdot\left[\begin{array}{ccc}0&-3&5\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-3%265%5C%5C0%261%262%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-2%5C%5C0%26-3%265%5Cend%7Barray%7D%5Cright%5D)
_____
The transformation of each ordered pair is ...
(x, y) ⇒ (-y, x)
Answer:

Step-by-step explanation:
We are required to reduce the expression below to its simplest form

<u>STEP 1: </u>Remove the brackets
Take note that the product of same sign(- and -) will give you the addition sign.

<u>STEP 2:</u> Find the Lowest Common Multiple of 8 and 6
Lowest Common Multiple of 8 and 6 is 24
<u>STEP 3:</u> Use the LCM to Simplify
Therefore:
