All categories

3 years ago

√70 is between which two numbers on the number line?

Mathematics

1 answer:

Leto [7]3 years ago

6 0

Answer:

C) 8 and 9

Step-by-step explanation:

We know that 70 is between two perfect squares.

The square numbers 64 and 81 can help us solve this question.

64<70<81

We take square root to get:

$\sqrt{64} \: < \: \sqrt{70} < \sqrt{81}$

We simplify this to get:

$8 \: < \: \sqrt{70} \: < \: 9$

Therefore √70 is between 8 and 9.

The correct option is C.

You might be interested in

Solve for x and find m∠FGH

mel-nik [20]

Answer:

x° = 11°

Z FGI = 60°

Step-by-step explanation:

If GH bisects Z FGI

then Z FGH = Z HGI

  or, (3x - 3)° = (4x - 14)°

or, 3x° - 4x° = - 14° + 3°

or, x° = 11°

Z FGI = 33° - 3° + 44° - 14°

 =  60°

3 0

3 years ago

1/2 cup of black beans provides 15% of the potassium you need daily you must get the remaining 2890 mg from another source how m

Alex787 [66]

3323.5 because if you times the number left by the 15 percent this is the answer.

3 0

4 years ago

Jackson has twice as many cards as his friends Alex and Chase combined. Alex has 55 Cards in his collection. Jackson Has 200 car

Zina [86]

Answer:

Step-by-step explanation:

200 divided by 2 = 100-55=45

8 0

3 years ago

Read 2 more answers

HELPPPPP PLEASEEEEE

Salsk061 [2.6K]

Answer:- 1/2

Step-by-step explanation:

4 0

3 years ago

Prove the divisibility: 45^45·15^15 by 75^30

garri49 [273]

Answer:

$3^{75}$ .

Step-by-step explanation:

We have been an division problem: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(9*5)^{45}=9^{45}*5^{45}$

$15^{15}=(3*5)^{15}=3^{15}*5^{15}$

$75^{30}=(15*5)^{30}=15^{30}*5^{30}$

Substituting these values in our division problem we will get,

$\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}$

$\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}$

$\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}$

$\frac{3^{105}*5^{60}}{3^{30}*5^{60}}$

$\frac{3^{105}}{3^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{105}}{3^{30}}=3^{105-30}$

$3^{105-30}=3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

7 0

3 years ago