the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
The car travelled 200 meters
20 m/s times 10 = 200 m in 10 s
Answer:
a+c=27
195a+320c=6515
Step-by-step explanation:
adult (a): 195
children (c): 320
total $: $6515
child $: 27
a+c=27 --> c=-a+27
195a+320c=6515
sub the first equation into the 2nd equation to get a=17
sub a=17 into c=-a+27 to get c=10
so, an adult ticket is $17 and a child ticket is $10.
