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Tasya [4]
3 years ago
11

I got 60 right out of 110 questions on a test. What was my overall grade/percentage?

Mathematics
2 answers:
Margaret [11]3 years ago
6 0
What you do is you make it into a fraction. You got 60 out of 110, so that's 60<u />/110. Because all fractions are practically division problems, that's 60 ÷ 110 = 0.5454545454...
Times that by 100 to get the percentage.
Ann [662]3 years ago
6 0
<u>Ans</u><u>-</u><em><u>YOUR OVERALL PERCENTAGE IS </u></em><u>54%</u>
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Answer:

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Step-by-step explanation:

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3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

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The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

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Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

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For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

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3 years ago
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