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Oxana [17]
3 years ago
12

PLEASE HELP! First one gets brainliest!

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

s = ∛756

Step-by-step explanation:

The volume of a cube is found by V = s³. To solve for the side of a cube with a specific volume, we use inverse operations to find it. s = ∛V. If the volume is 756 then the s = ∛756.

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I need help with this please. :)
stepladder [879]

Answer:

64x³+4

-------------

2x-1

Step-by-step explanation:

I hope this helps. :)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B
ankoles [38]

\bold{Heya!}

Your answer to this is:

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u />\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)

\sf{Apply \: rule:} \: (a) = a

\sf{(1) = 1

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1

\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}

\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

7 0
2 years ago
Answer all &amp; show work! WILL MARK BRAINLIEST!
Eddi Din [679]

Answer:

Step-by-step explanation:

1 12

2 19

3 10

4 28

5 2

6 0
3 years ago
Anyone please help me i'm not sure how to do this and please give clear instructions
rewona [7]
-10= 7X - 42
-10 + 42 = 7X
32 = 7X
X = 32/7
X = 4.57
7 0
3 years ago
Ina survey at a supermarket, 78 out of 120 people surveyed said that they shopped more than ounce a week. What percent of the pe
goldfiish [28.3K]

78 /120 =0.65

0.65 x 100 = 65%

the answer is 65%

4 0
3 years ago
Read 2 more answers
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