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ira [324]
3 years ago
14

Solve the following system of equations:

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

(1,3)

Step-by-step explanation:

\sf Answer\begin{cases} \sf \rightarrowtail \:  - 2x + y = 1 \dots(1) \\  \sf \rightarrowtail \:  - 4x + y =  - 1 \dots(2) \\ \sf 2 \times (1) \implies - 4x + 2y  = 2 \\ \sf 1 \times (2) \implies - 4x + y =  - 1 \\  \bf \star \: substracting \: both \\  \sf \rightarrowtail \: y = 3 \\  \sf \rightarrowtail \: -2x+(3)=1 \\ \sf \rightarrowtail \: -2x=-2 \\  \sf \rightarrowtail \: x=1\end{cases}

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Step-by-step explanation:

The reason why I say this is because if you plot both graphs on one cordinate plance, you can see that the difference between the two graphs is that the graph of f(x) HAS BEEN SHIFTED DOWN 6 UNITS.As a result, the correct answer choice is B.Hope that helped @user.


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2 years ago
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tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

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