Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.
Let us find z-score of data point 22.03.
Using probability formula 
, we will get:
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Kilograms per cubic centimeter
The Lesser Sooty Owl is a strictly nocturnal bird. Hides & sleeps during the day in dense foliage, between tangles of aerial roots, in all kinds of crevices, or beneath overhanging banks. Hunts in clearings and near roads, but also inside forest.
Using a calculator, it is found that for the two-tailed test of significance, the p-value is of 0.9195.
The correlation coefficient is also called <u>Pearson's r-score</u>, and is used for two-tailed tests. To find the p-value, the information needed is:
- The value of the Pearson's r-score, that is, the value of the correlation coefficients.
- The sample size.
In this problem, we have that the correlation coefficient is of r = 0.02, with a sample size of n = 28.
- Using it as the input for a r-score calculator, the p-value is of 0.9195.
A similar problem is given at brainly.com/question/13873630
Answer:
cant see i am dumb
Step-by-step explanation:
and blind i cant see at all my gide dog wrote dis woof woof
