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9966 [12]
2 years ago
6

You are planning a storage solution for a new Windows server. The server will be used for file and print services and as a datab

ase server. The new server has five hard disks, all with equal capacity. Your storage solution should meet the following requirements: System files should be on a volume separate from data files. All volumes should be protected so that the server can continue to run in the event of a failure of one of the disks. The data volume should be optimized for improved disk access times. You will use Windows Disk Management to create and manage the volumes. What should you do
Computers and Technology
1 answer:
maks197457 [2]2 years ago
8 0

Answer:

Explanation:

The best solution for this scenario would be to first create a mirrored volume for the system volume using two of the available disks and then a single RAID 5 volume with the remaining 3 disks for the data volume. This setup will allow all of the data to be backed up so that if one of the disks fails the server will continue running accordingly. The RAID 5 volume offers error checking and redundancy for the data, therefore, allowing the data to be accessed quickly and efficiently with far greater security and far less chance of data becoming corrupt.

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Answer:

The complete program is as follows:

def convert_distance(miles):

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# 2) Convert my_trip_miles to kilometers by calling the function above

my_trip_km =convert_distance(my_trip_miles) #3) Fill in the blank to print the result of the conversion

# 4) Calculate the round-trip in kilometers by doubling the result,

print("The distance in kilometers is " +str(my_trip_km))

# and fill in the blank to print the result

print("The round-trip in kilometers is " + str(my_trip_km * 2))

Explanation:

<em>The program is self-explanatory because I used the same comments in the original question.</em>

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3 years ago
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Which single OSPF network statement will correctly include all the interfaces on a device whose IP addresses only begin with a 1
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Explanation:

<em>show ip ospf interface </em>

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<em />

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