◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
Answer:
81
Step-by-step explanation:
12/3 = 4
4 - 2 = 2
x = 2
using the order of operations, you would first have to do y + 3
y = 12
12 + 3 = 15
the equation simplified is 3 x 2 + 5 x 15
3 x 2 = 6
5 x 15 = 75
75 + 6 = 81
Because there are 9 fruits, it should be n/9, depending on the fruit.
Apples are 2/9, so:
The combination for apples would have a probability of 2/9<span />
