$\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot \frac{ \sqrt{2} }{2}=- \frac{ \sqrt{6} }{4} - \frac{ \sqrt{2} }{4}= -\frac{ \sqrt{6}+\sqrt{2} }{4}$

5 0

3 years ago

Please help! Important

guapka [62]

Add the two angles and set them equal to 180, them solve for x

3 0

3 years ago

Read 2 more answers

What is the answer? -3(6w-3v-1)

SashulF [63]

This is the best way to show you step by step. i love this website/app it’s called Math papa and you type in your problem and it helps you with the steps. this is how i got so good at math.

4 0

3 years ago