What is the y-value in the solution to this system of linear equations?
2 answers:
Answer:
Option A.)−4
Step-by-step explanation:
we have
4x+5y=-12 -----> equation A
-2x+3y=-16 -----> equation B
Solve the system of equations by elimination
Multiply the equation B by 2
2*(-2x+3y)=-16*2
-4x+6y=-32 -----> equation C
Adds equation A and equation C
4x+5y=-12
-4x+6y=-32
-----------------
5y+6y=-12-32
11y=-44
y=-4
Answer with Step-by-step explanation:
We are given a system of linear equations:
4x + 5y = −12
-2x + 3y = −16
Multiply second equation by 2 and add it to first equation.
4x+5y-4x+6y= -12-32
⇒ 11y= -44
Dividing both sides by 11
⇒ y= -4
Hence, the y-value in the solution to the system of linear equations
4x + 5y = −12
-2x + 3y = −16 is:
A.)−4
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