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3 years ago

6

Suppose you start at the origin, move along the x-axis a distance of 4 units in the positive direction, and then move downward a

long the z-axis a distance of 5 units. What are the coordinates of your position? (x, y, z)

1 answer:

Zanzabum3 years ago

3 0

Answer:

(4,0,-5)

Step-by-step explanation:

Since we move 4 points along +ve x-axis so, x coordinate is 4

We did not move any point along y-axis so y coordinate is 0

we moved 5 points along -ve z-axis so z coordinate is -5

so our position is (x,y,z) = (4,0,-5)

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In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?

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General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

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$f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a} .\\\\f(ax), \; 0$

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

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Cora babysat for 3 1/2 hours and charged at $28. At the same hourly rate, what would she charge for 5 1/2 hours of babysitting?

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A baseball player throws a 95mph fastball straight up into the air. The position equation, which gives the height of the ball at

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3 years ago

Use a graph to solve the equation. Check your solution.

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3 years ago

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

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Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a <em>normal distribution </em>with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

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2 years ago