Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
x = 2, -3
Step-by-step explanation:

(x-2) = 0 or (x+3) = 0
x = 2 or x = -3
Thus, two values of x are x = 2, -3
Note: The options given are incorrect.
Answer:
DWAFECGSAD
Step-by-step explanation:
EWAFGSEE
$1.60
Divide 80 by 50 to find the cost of one brownie which will then lead you to get you the answer of $1.60
Answer:
7g+3h
Step-by-step explanation:
you combine like terms by adding 3g and 4g and subtracting 2h from 5h.