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Nat2105 [25]
3 years ago
13

(3×+5)(2×+10)= then x=

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0
X= -5/3 & x=5
I got this by using the quadratic formula.
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Answer:

N = 10

Step-by-step explanation:

-17+ x/5 = 33

You have to find x, in this case is N

x/5 = 33 + 17

x/5 = 50

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N= 10

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Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
Find the 6 trìg functions
mars1129 [50]

I hope this helps you

let's find AB

AB=square root of 2^2+3^2

AB=square root of 13

cosO=2/sqrt13

sinO=3/sqrt13

tgO=3/2

ctgO=2/3

6 0
2 years ago
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