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hammer [34]
3 years ago
12

X-3y^3+3x^3-5x-x^3-x-2x^3

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
7 0

Answer:

-5x-3y^3

Step-by-step explanation:

x-3y^3+3x^3-5x-x^3-x-2x^3

Eddi Din [679]3 years ago
3 0

\huge\text{Hey there!}

\large\boxed{\mathsf{x - 3y^3 + 3x^3 - 5x - x^3 - x - 2x^3}}

\large\text{COMBINE the LIKE TERMS}

\large\boxed{\mathsf{= (3x^3 - x^3 - 2x^3) + (-3y^3) + (x - 5x - x)}}

\large\boxed{\mathsf{= 3x^3 - x^3 - 2x^3 - 3y^3 + x - 5x - x}}

\large\boxed{\mathsf{= -3y^3 - 5x}}

\huge\boxed{\rm{Therefore, your \ answer \ is: -3y^3 - 5x}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
What is 8,170 divided by 75 equal
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108.93

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4 0
3 years ago
3. What is the estimated probability that teens spend less than an hour per day texting?
DaniilM [7]

Answer:

0.29

Missing Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random  

sample of 870 teenagers aged 13–18 in a large urban city.  

Hours          0     0.5    1.0   1.5  2.0   2.5  3.0  3.5  4.0  4.5  5.0

Frequency  170  82    220  153  92   58   40    15  12   18    10

Step by Step Explanation:

First we need to find the estimated probability distribution for teens spending time texting.

For that we need,

Total sample size = 870 teenagers (as given in the problem statement)

Estimated probability distribution (Frequency*) = \frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}

Example:

Estimated probability distribution that teens spend 0 hours=\frac{170}{870} =0.20

Similarly,

Hours          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

Frequency*0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

We need, estimated probability distribution that teens spend less than an hour per day, so from the above result:

<u>Estimated probability distribution of teens spending 0 hour per day =0.2 </u>

<u>Estimated probability distribution of teens spending 0.5 hour per day = 0.09 </u>

Estimated probability distribution of teens spending less than an hour per day= 0.2+0.09=0.29

4 0
3 years ago
Read 2 more answers
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Answer:

(5, 21)

Step-by-step explanation:

The x-coordinate of the midpoint of a segment is half of the sum of the x-coordinates of the endpoints.

The y-coordinate of the midpoint of a segment is half of the sum of the y-coordinates of the endpoints.

Let the unknown point have coordinates (x, y).

x-coordinate:

(5 + x)/2 = 5

5 + x = 10

x = 5

y-coordinate:

(-1 + y)/2 = 10

-1 + y = 20

y = 21

The other endpoint has coordinates (5, 21).

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