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hammer [34]
3 years ago
12

X-3y^3+3x^3-5x-x^3-x-2x^3

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
7 0

Answer:

-5x-3y^3

Step-by-step explanation:

x-3y^3+3x^3-5x-x^3-x-2x^3

Eddi Din [679]3 years ago
3 0

\huge\text{Hey there!}

\large\boxed{\mathsf{x - 3y^3 + 3x^3 - 5x - x^3 - x - 2x^3}}

\large\text{COMBINE the LIKE TERMS}

\large\boxed{\mathsf{= (3x^3 - x^3 - 2x^3) + (-3y^3) + (x - 5x - x)}}

\large\boxed{\mathsf{= 3x^3 - x^3 - 2x^3 - 3y^3 + x - 5x - x}}

\large\boxed{\mathsf{= -3y^3 - 5x}}

\huge\boxed{\rm{Therefore, your \ answer \ is: -3y^3 - 5x}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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after filling her gas tank, katie drove 159.75 miles. after the ride. she filled her tank again with 7.1 gallons of gas. on aver
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3 years ago
How many times does the quadratic function below intersect the x-axis?<br> y = 2x2 +7x+6
sattari [20]

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once

Step-by-step explanation:

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6 0
3 years ago
Please help me!!!!! How do you get 67.3 and 112.7 from .9228
antoniya [11.8K]

Answer and Step-by-step explanation:

You are correct in that we need to use the Law of Sines: \frac{c}{sinC} =\frac{b}{sinB}=\frac{a}{sinA}.

Here, when we use the Law of Sines, we have: \frac{28}{sin(63)}=\frac{29}{sinB}.

Cross multiply:

(sinB) * 28 = (sin63) * 29

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Now, in order to solve for B, we need to use inverse sin (sin^{-1}):

sin^{-1}(sinB)=sin^{-1}(0.9228)

The sines on the left cancel out, and we're left with:

B ≈ 67.3 degrees

Now, one thing to keep in mind when doing Law of Sines is that there is potentially more than one answer possible for the degree measure. The other degree measure can be found by subtracting this one from 180:

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Hope this helps!

7 0
3 years ago
Read 2 more answers
The mean survivial time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years. Based on a parti
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Answer:

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Step-by-step explanation:

It is provided that the mean survival time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years.

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An individual's predicted survival time is <em>a</em> = 2.8 standard deviations beyond the mean.

Compute the time the patient expected to survive after diagnosis as follows:

X=\mu+a\sigma

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Thus, the time the patient expected to survive after diagnosis is 29 years.

5 0
3 years ago
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