All categories

3 years ago

X-3y^3+3x^3-5x-x^3-x-2x^3

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

7 0

Answer:

-5x-3y^3

Step-by-step explanation:

x-3y^3+3x^3-5x-x^3-x-2x^3

Eddi Din [679]3 years ago

3 0

$\huge\text{Hey there!}$

$\large\boxed{\mathsf{x - 3y^3 + 3x^3 - 5x - x^3 - x - 2x^3}}$

$\large\text{COMBINE the LIKE TERMS}$

$\large\boxed{\mathsf{= (3x^3 - x^3 - 2x^3) + (-3y^3) + (x - 5x - x)}}$

$\large\boxed{\mathsf{= 3x^3 - x^3 - 2x^3 - 3y^3 + x - 5x - x}}$

$\large\boxed{\mathsf{= -3y^3 - 5x}}$

$\huge\boxed{\rm{Therefore, your \ answer \ is: -3y^3 - 5x}}$ $\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

You might be interested in

SOLVE FOR X -5x + 9 = 24

boyakko [2]

Answer:

x = -3

Step-by-step explanation:

-5x + 9 = 24

move the nine to the other side

-5x = 15

divide

x = -3

7 0

3 years ago

Help please.........

Lunna [17]

I am not sure, but the answer is probably option A. Graph A.

5 0

4 years ago

I have 30 question test and need 70% to pass how many questions can be wrong

alekssr [168]

Total questions are 30.

70% of 30
=30(70/100)
=21

So, the questions can be wrong are 30-21.
=9 questions..

Thanks!

3 0

3 years ago

There is a line through the origin that divides the region bounded by the parabola y=2x-4x^2 and the x-axis into two regions wit

shtirl [24]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

y = 7x - 4x²

7x - 4x² = 0 

x(7 - 4x) = 0 

x = 0, 7/4 

Find the area of the bounded region... 

A = ∫ 7x - 4x² dx |(0 to 7/4) 

A = 7/2 x² - 4/3 x³ |(0 to 7/4) 

A = 7/2(7/4)² - 4/3(7/4)³ - 0 = 3.573 

Half of this area is 1.786, now set up an integral that is equal to this area but bounded by the parabola and the line going through the origin... 

y = mx + c 

c = 0 since it goes through the origin 

The point where the line intersects the parabola we shall call (a, b) 

y = mx ===> b = m(a) 

Slope = m = b/a 

Now we need to integrate from 0 to a to find the area bounded by the parabola and the line... 

1.786 = ∫ 7x - 4x² - (b/a)x dx |(0 to a) 

1.786 = (7/2)x² - (4/3)x³ - (b/2a)x² |(0 to a) 

1.786 = (7/2)a² - (4/3)a³ - (b/2a)a² - 0 

1.786 = (7/2)a² - (4/3)a³ - b(a/2) 

Remember that (a, b) is also a point on the parabola so y = 7x - 4x² ==> b = 7a - 4a² 
Substitute... 

1.786 = (7/2)a² - (4/3)a³ - (7a - 4a²)(a/2) 

1.786 = (7/2)a² - (4/3)a³ - (7/2)a² + 2a³ 

(2/3)a³ = 1.786 

a = ∛[(3/2)(1.786)] 

a = 1.39 

b = 7(1.39) - 4(1.39)² = 2.00 

Slope = m = b/a = 2.00 / 1.39 = 1.44

7 0

3 years ago

1. The county fair charges $1.50 per ticket for the rides. Jermaine bought 20 tickets for the rides and spent a total of $48.75

MAVERICK [17]

Answer: Our variable be z for fair admission and our required linear equation will be

$\$1.50x+z=\$48.75$

Explanation:

Since we have given that

Cost per ticket for the rides =$1.50

Total amount she spent = $48.75

Let the total cost be y

Let the number of ride tickets be x

a) Define your variable:

Let the amount spent on fair admission be z

b) Write a linear equation that can be used to determine the cost for ride tickets and fair admission:

Our required equation will be

$\$1.50x+z=\$48.75$

Here, number of ride tickets = 20

So,

$20\times 1.50+z=48.75\\\\30+z=48.75\\\\z=48.75-30=18.75$

So, the cost for fair admission = $18.75

7 0

4 years ago