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finlep [7]
3 years ago
13

NEED ANSWER STAT

Mathematics
1 answer:
WITCHER [35]3 years ago
5 0

Answer:

B, F, G

Step-by-step explanation:

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What is four million,nine hundred thirty-five in standard form
Bad White [126]
4,000,000,39

there you go!
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3 years ago
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Listen Find the area of a triangle whose vertices are (1, 2), (8, 2), and (1, 6
docker41 [41]

check the picture below, you can pretty much count the units off the grid.

recall that A = (1/2)bh.

7 0
3 years ago
What is 5.921 to the nearest hundredth
lukranit [14]
It would be 5.92 because when you round to a certain place, you base it off of the number to the right of that place. Since 1 is less than 5 you would keep everything before 1 the same and make the 1 a zero.
4 0
3 years ago
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central angle of a sector is 72° and the sector has an area of 16.2(pie) ft^2. what is the radius of the circle?
Cloud [144]
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sector area = (72 / 360) * PI * radius^2
radius^2 = sector area / [(72 / 360) * PI]
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Source:
http://www.1728.org/radians.htm



6 0
4 years ago
Solve the following differential equation: (2x+5y)dx+(5x−4y)dy=0 *Hint: they are exact<br><br> C=.
Tpy6a [65]

Answer with Step-by-step explanation:

The given differential equation is

(2x+5y)dx+(5x-4y)dy=0

Now the above differential equation can be re-written as

P(x,y)dx+Q(x,y)dy=0

Checking for exactness we should have

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial y}=\frac{\partial (2x+5y)}{\partial y}=5

\frac{\partial Q}{\partial x}=\frac{\partial (5x-4y)}{\partial x}=5

As we see that the 2 values are equal thus we conclude that the given differential equation is exact

The solution of exact differential equation is given by

u(x,y)=\int P(x,y)dx+\phi(y)\\\\u(x,y)=\int (2x+5y)dx+\phi (y)\\\\u(x,y)=x^2+5xy+\phi (y)

The value of \phi (y) can be obtained by differentiating u(x,y) partially with respect to 'y' and equating the result with P(x,y)

\frac{\partial u}{\partial y}=\frac{\partial (x^2+5xy+\phi (y)))}{\partial y}=Q(x,y))\\\\5y+\phi '(y)=(5x-4y)\\\\\phi '(y)=5x-9y\\\\\int\phi '(y)\partial y=\int (5x-9y)\partial y\\\\\phi (y)=5xy-\frac{9y^2}{2}\\\\\therefore u(x,y)=x^2+10xy-\frac{9y^2}{2}+c

5 0
3 years ago
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