Answer: (-9,6)
Step-by-step explanation:
3x+2y=-15
2x=-18
First solve for x in second equation
2x=-18
2x/2=-18/2
X= -9
Now substitute your x into first equation to find y
3(-9)+2y= -15
-27+2y=-15
2y= -15+27
2y= 12
2y/2=12/2
Y= 6
We have to calculate the amount of money Peter will have in his account after 5 years. Formula for the amount after t years with interest compounded continuously : A = P * e ^(rt)
We know that r = 0.06, t=5, e = 2.71 and p= $8,000
A = 8,000 * 2,718 ^(0.06 * 5) = 8,000 * 2,718 ^ (0.3) = 8,000 * 1.3488158 = 10,798.53 so the answer is 10,798.53
Answer:
Let X be the number of times the target is hit. The probability P(X≥1) then equals 1 minus the probability of missing the target three times:
P(X≥1) = 1− (1−P(A)) (1−P(B)) (1−P(C))
= 1−0.4*0.3*0.2
= 0.976
To find the probability P(X≥2) of hitting the target at least twice, you can consider two cases: either two people hit the target and one does not, or all people hit the target. We find:
P(X≥2)=(0.4*0.7*0.8)+(0.6*0.3*0.8)+(0.6*0.7*0.2)+(0.6*0.7*0.8) = 0.788
Step-by-step explanation:
C. y - 3 = 2/3(x-3)
Nothing much to do here except examine each equation and plug in the numbers to see if it's true.
a. y + 3 = 3/2(x+3)
Try 3,3
3 + 3 = 3/2(3+3)
6 = 3/2(6). And no need to go further, it's obviously not equal.
b. y - 3 = 3/2(x-3)
Try 3,3
3 - 3 = 3/2(3-3)
0 = 3/2(0). OK. Let's try 6,5
5 - 3 = 3/2(6-3)
2 = 3/2(3)
2 = 9/2 And it's not true, so check the next one.
c. y - 3 = 2/3(x-3)
Try 3,3
3 - 3 = 2/3(3-3)
0 = 0. Check 6,5
5 - 3 = 2/3(6-3)
2 = 2/3(3)
2 = 2. Good. Both sample points work. This is the correct answer.
Just to be sure, let's check the next option
d. y + 3 = 2/3(x+3)
Try 3,3
3 + 3 = 2/3(3+3)
6 = 2/3(6). And doesn't match.
