The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
Read more about vertex at:
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Answer:
x = -1
Step-by-step explanation:
5x + 5 = 0
Subtract 5 from each side
5x+5-5 = 0-5
5x = -5
Divide by 5 on each side
5x/5 = -5/5
x = -1
Answer:
dee y by dee x
Step-by-step explanation: hope this helps! have a supercalifragilisticexpialidocious day! ◑﹏◐
Answer:
x = -5/2 + i√19 and x = -5/2 - i√19
Step-by-step explanation:
Next time, please share the possible answer choices.
Here we can actually find the roots, using the quadratic formula or some other approach.
a = 1, b = 5 and c = 11. Then the discriminant is b^2-4ac, or 5^2-4(1)(11). Since the discriminant is negative, the roots are complex. The discriminant value is 25-44, or -19.
Thus, the roots of the given poly are:
-5 plus or minus i√19
x = -----------------------------------
2(1)
or x = -5/2 + i√19 and x = -5/2 - i√19
Answer:
Step-by-step explanation:
-40x + 8y = -24
3x - 8y = 24
-37x = 0
x = 0
0 + y = -3
y = -3
(0, -3)
