The value of x so that lines s and t are parallel is 12
<h3 /><h3>How to find angles involving parallel lines?</h3>
The angle are alternate exterior angles.
Therefore, alternate exterior angle theorem states that when two parallel lines are intersected by a transversal, then the exterior angles formed on either side of the transversal are equal.
Hence,
7x - 20 = 4x + 16
7x - 4x= 16 + 20
3x = 36
x = 36 / 3
x = 12
Therefore, the value of x is 12.
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First you need to find the slope of the line:

m=6-(-2) / (-1)-0 =-8
equation of line is:
y=mx+b
y=-8x+6
for absolute value function:
if x<0
y=-8x+6
if x>0
y=+8x-6
Answer:
3x^2 + 3xy/2 - 7xy^2/2
Step-by-step explanation:
So we know the perimeter is 20x^2 + xy - 7y^2,
To find any perimeter you need 2l + 2w = P so,
One of the sides is 7x^2 - xy
First plug in the values,
2(7x^2-xy) + 2w = 20x^2 + xy - 7y^2
Multiply,
14x^2-2xy + 2w = 20x^2 + xy - 7y^2
Subtract,
14x^2 - 2xy - 14x^2 + 2xy + 2w = 20x^2 + xy - 7y^2 - 14x^2 + 2xy
2w = 6x^2 + 3xy - 7y^2
w = 3x^2 + 3xy/2 - 7xy^2/2