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3 years ago

What is the point slope point form of the line with slope -3/7 that passes through the point (5,8)

Mathematics

1 answer:

Talja [164]3 years ago

7 0

Answer:

The point slope form of this equation would be D) y - 8 = -3/7(x - 5)

Step-by-step explanation:

In order to find this, we simply plug in the information known into point-slope form, which is listed for you below.

y - y1 = m(x - x1)

y - 8 = -3/7(x - 5)

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Find each percent increase round to the nearest percent from $5 to $8

asambeis [7]

First subtract the two numbers:

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Now divide this to the original:

3 / 5 = 0.6

Multiply by 100:

0.6 * 100 = 60%

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3 years ago

24-4x=32<br><br><br> Show your work

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Answer:

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24 - 4x =32

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nata0808 [166]

6 1/6, 5.5, 4 3/8, 4.3, 15/4

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3 years ago

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

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3 years ago