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MrRissso [65]
3 years ago
5

Sadie finished her math test in sixteen minutes less than three times the amount of times it took her friend Laura to finish.if

their combined times was 1 hour and 8 minutes,how long did it take Sadie?
Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

Sadie took 47 minutes to finish her test.

Step-by-step explanation:

Let Laura's time be x minutes.

Then we have:

x + 3x - 16 = 68

4x = 84

x = 21 minutes.

So Sadie took 3(21) - 16 = 63-16

= 47 minutes.

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Luna is competing in a 200 m race.
Yuri [45]

Answer:

24

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
If there are 42 boys and 54 girls in a room, fill out all of the possible
Setler79 [48]

Answer:

21:27 and 14:18

Step-by-step explanation:

We can solve this by using common factors

one of the common factors of 54 and 42 is 3

42/3=14

54/3=18

so one of the ratios is 14:18

another common factor is 2

42/2=21

54/2=27

so another ratio is 21:27

4 0
3 years ago
Question Category: Solving Quadratic Equations by Factoring Select the correct answer. Find the solution(s) for x in the equatio
Novay_Z [31]

Answer: x = 4; x = 5

Step-by-step explanation:

The directions specify to solve by factoring

x^2 - 9x + 20 = 0

To factor, find two numbers that add to -9 and multiply to 20

-5 and -4 work

-5 + (-4) = -9

-5 * -4 = 20

(x - 4)(x - 5) = 0

x = 4, x =5

6 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Which is a true statement?
Shkiper50 [21]
A) -15 > -5 is false.
B) -4 > 0 is 0 < -4
C) -12 < -3 is always true. There are many solutions.
D) 2 < -5 is false.

Answer: C) -12 < -3
6 0
3 years ago
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