Make each fraction have a like denominator
7/9 * 8/8= 56/ 72
7/8 * 9/9 = 63/72
18 + 14 + (56+63)/72
32 + 119/72
32 + 1 + 47/72
33 and 47/72
Answer:
Holy bloop you gotta learn
Step-by-step explanation:
you dumb
go to school
and learn
<h2>
Answer:</h2>
<h2>
Step-by-step explanation:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
<em />
First of all, let's name the first variable which is the smaller number. Accordingly, the lager number will be given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:
So:
1. The sum of 2 consecutive integers can be written as:
2. Nine times the smaller and 5 times the larger can be written as:
Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:
The two numbers are:
Answer:
Step-by-step explanation:
The accepted values are 2 3 4 5 6 One is not counted. It says between.
The total number of ways each dice can be thrown is 2 3 4 5 6 7 8 9 Ten is not counted. Same reason.
5/8 * 5/8 = 25/64 = 0.39