2 years ago

How do i find a value of x in angles and similarity

Mathematics

1 answer:

Mariulka [41]2 years ago

6 0

Add up the other angle or angles. take 180 and subtract from what you got

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Consider the vector field f(x,y,z)=(2z+3y)i+(3z+3x)j+(3y+2x)kf(x,y,z)=(2z+3y)i+(3z+3x)j+(3y+2x)k.

natima [27]

$\dfrac{\partial f}{\partial x}=2z+3y\implies f(x,y,z)=2xz+3xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=3x+\dfrac{\partial g}{\partial y}=3z+3x$
$\dfrac{\partial g}{\partial y}=3z\implies g(y,z)=3yz+h(z)$
$\implies f(x,y,z)=3xz+3xy+3yz+h(z)$

$\dfrac{\partial f}{\partial z}=3x+3y+\dfrac{\mathrm dh}{\mathrm dz}=3y+2x$
$\dfrac{\mathrm dh}{\mathrm dz}=-x$

But we assume $h$ is a function of $z$ alone, so there is no solution for $h$ and hence no scalar function $f$ such that $\nabla f=\mathbf f$ .

6 0

2 years ago

Pls help !<br> i need help with all 3 questions quick

Zarrin [17]

Ask your mummy......

6 0

3 years ago

Can someone Help me in this problem?

Fed [463]

If you have to write the equation then it would be "5k + 6.7"

5 0

3 years ago

It is found that 5 out of every 8 college students like algebra. If a certain college has 4,000 students, how many of them like

solniwko [45]

5 out of 8 turned into a fraction is 5/8. 5/8 turned into a percentage is 62.5%. 62.5% of 4,000 is 2,500. 2,500 students in the college like algebra.
Hope this helped.

3 0

3 years ago

Read 2 more answers

0.09×0.7 <br>help me please

dem82 [27]

0.09x0.7= 0.063

That its the answer

7 0

3 years ago