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sergij07 [2.7K]
3 years ago
10

A container is shaped like a cylinder with half spheres on each end the cylinder has a length of 30 centimeters and a radius of

5 cm to the nearest cubic centimeter how many cubic centimeters can one container hold do not round calculations until the final answer
Mathematics
2 answers:
4vir4ik [10]3 years ago
7 0
The container is aproximatly 1064.16 cm^2

Volume of a cylinder (area of the base* height) + area of the sphere (4 *pi * r^2)
(25*30) + (4* pi * 25) = 750 + 314.15926535898 = 1064.15926535898
Leviafan [203]3 years ago
6 0
<h2>Answer:</h2>

The volume of the container is:

                 2880 cm^3

<h2>Step-by-step explanation:</h2>

In order to find the volume of the container we need to find the volume of the cylinder and volume of two  half spheres.

i.e.

Volume of container=Volume of cylinder+Volume of two half spheres.

We know that the volume of cylinder is given by:

\text{Volume\ of\ cylinder}=\pi r^2h

where h is the height of the cylinder and r denote the radius of the cylinder.

Also, volume of 1 half sphere is given by:

\text{Volume\ of\ half\ sphere}=\dfrac{2}{3}\pi r^3

where r is the radius of half sphere.

Hence, Volume of 2 half spheres is:

\text{Volume\ of\ two\ half\ sphere}=\dfrac{4}{3}\pi r^3

Hence,

\text{Volume\ of\ container}=\pi r^2h+\dfrac{4}{3}\pi r^3

From the given information in the question we have:

r=5\ cm\\\\h=30\ cm\\\\We\ use\ \pi=3.14

Hence, by putting these values in the expression (1) and solving we get:

\text{Volume\ of\ container}=2879.7932\ cm^3

which on rounding off gives:

           2880 cm^3

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AfilCa [17]

Answer:

h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.

JP=5\sqrt{3}\ cm

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

h=\dfrac{a\sqrt{3}}{2},

where a is the side length.

So,

h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.

Therefore JP is 5√3 cm

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