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Lesechka [4]
3 years ago
7

What is the simplified form of -(14X)^0y^-7z-14z/y^714z/y^7z/y^7-z/y^7

Mathematics
2 answers:
zhuklara [117]3 years ago
4 0
((-196z^3)/(y^21))-(2z/y^7)
Goryan [66]3 years ago
3 0
Anything to the 0 power is 1
so we get
-1y⁻⁷z
(-1)(y⁻⁷)(z)
and x^{-m}= \frac{1}{x^m}
(-1)(y^{-7})(z)= \frac{(-1)(z)}{y^7} = \frac{-z}{y^7}

last option

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8-5c=-37 help please :)
ladessa [460]

Answer:

c=9

Step-by-step explanation

8-5c=-37

-37-8= -5c

-45= -5c

-45/-5=c

c=9

6 0
3 years ago
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5(z+4)+5(2−z) simplyfied
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Answer:

5(z+4) + 5(2-z) =

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Melissa walked at a rate of 88 feet per minute. What was her approximate speed to the nearest tenth of a mile
Illusion [34]

88x60=5280

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Ryan is building a tree house it will take 13 1/4 hours to complete he can work on the tree house 1 1/2 hours each day how many
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5 0
3 years ago
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

3 0
3 years ago
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