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SOVA2 [1]
4 years ago
6

How much kinetic energy does a 4 kg cats have while at 9 m/s​

Mathematics
1 answer:
coldgirl [10]4 years ago
7 0

Answer:

162 Joules

Step-by-step explanation:

Remember, the equation for the kinetic energy of an object is:

K=\frac{1}{2}mv^{2}

where m is the mass of the object in kg (kilograms), v is the velocity of the object in m/s (meters per second), and K is the kinetic energy of the object in J (joules).

We are given that the cat's mass is 4 kg. We will use this for m. We are also given that the cat is moving at 9 m/s. This would be it's speed. We can use this for velocity, or v. Plugging in we get:

K=\frac{1}{2}mv^{2}=\frac{1}{2}(4)(9)^{2}=(2)(81)=162

So K, or the kinetic energy, would be 162J.

I hope you find my answer and explanation to be helpful. Happy studying.

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A circle has a sector with area 1/2pi and central angle of 1/9pi radians what is the area of the circle?
Mazyrski [523]

Answer:

Step-by-step explanation:

It’s daddy

4 0
3 years ago
Solve: (x + 5)^2 + 15 = 64
ch4aika [34]
(x+5)^2 = 49;
Then x + 5 = 7 or x + 5 = -7 ;
Finally, x = 2 or x = -12.
5 0
4 years ago
Standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 deg
exis [7]

Answer:

(a). 2399.23 meters.

(b). 1944.19 meters apart.

Step-by-step explanation:

Please find the attachment.

We have been given that standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 degrees.

(a) We are asked to find how far from the shore is the ship.

We know that tangent relates opposite side of a right triangle with its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(9^{\circ})=\frac{380}{x}

x=\frac{380}{\text{tan}(9^{\circ})}

x=\frac{380}{0.158384440325}=2399.22557

Therefore, the ship is approximately 2399.23 meters away from the shore.

\text{tan}(5^{\circ})=\frac{380}{x+y}

x+y=\frac{380}{\text{tan}(5^{\circ})}

x+y=\frac{380}{0.087488663526}

2399.22557+y=4343.419875

y=4343.419875-2399.22557

y=1944.194305\approx 1944.19

Therefore, the both ships are approximately 1944.19 meters apart.

7 0
4 years ago
Discrete math
nadya68 [22]

Answer:

1) yes

2) No

3) No

4) yes

5) No

Step-by-step explanation:

1) f(0)=0, f(1)=1, f(2)=2, f(3)=3, then f[\{0, 1, 2, 3\}]=\{0, 1, 2, 3\}

2) f(0)=0, 1^2=1\equiv 1 \text{mod 4}, then f(1)=1; 2^2=4\equiv 0 \text{ mod 4}, then f(2)=0; 3^2=9\equiv 1 \text{mod 4}, then f(3)=1

Then f[\{0, 1, 2, 3\}]=\{0, 1, 3\}, this means that f isn't onto.

3.

  • f(0)=0;
  • 1^1-1=0, then f(1)=0
  • 2^2-2=2, then f(2)=2
  • 3^2-3=6\equiv 2 \text{ mod 4}, then f(3)=2

Then  f[\{0, 1, 2, 3\}]=\{0, 2\}, this means that f isn't onto.

4.  f[\{0, 1, 2, 3\}]=\{0, 1, 2,3\}, then f is onto.

5. f[\{0, 1, 2, 3\}]=\{1, 2\}, this means that f isn't onto.

6 0
3 years ago
Help anyone please hurry!!!
velikii [3]
G=25.5

Steps:
Add 8 to both sides and you get g=25.5
4 0
3 years ago
Read 2 more answers
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