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In-s [12.5K]
3 years ago
13

Which expresión is equvalient yo 810-210+20+20

Mathematics
2 answers:
Maurinko [17]3 years ago
4 0

Answer:

The ANSWER is 640

Step-by-step explanation:

810 - 210 = 600 + 20 = 620 + 20 = 640

andrezito [222]3 years ago
3 0

Answer:

640

Step-by-step explanation:

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At a pet store, for every 4 male birds there are 7 female birds what is the ratio of female birds to male birds
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A - because 4 males : 7 females
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son4ous [18]
3/10 of 400 = 120
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The sum of 3 numbers is 131. the second of three numbers is seven more than twice the first. the third number is 12 less than th
arsen [322]
A+b+c = 131

b = 7 + 2a and c = a - 12
 so a + 7+2a + a-12 = 131
then 4a -5 = 131
then 4a = 136
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3 years ago
.45 is 1/10 of what?
jok3333 [9.3K]

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8 0
3 years ago
find zeros and y intercept and describe the end behavior in proper notation. then sketch the graph. 3x^3+2x^2-12x-8
Evgen [1.6K]

Answer: The zeros of the given equation are 2, -2 and -0.667. The y-intercept of the graph is f(0) = -8.

Explanation:

The given expression is,

f(x)=3x^3+2x^2-12x-8

To find zeros put f(x)=0

3x^3+2x^2-12x-8=0

This equation is satisfied by x=2, so (x-2) is the factor of the given equation. By synthetic division or long division we can find the remaining factor.

(x-2)(3x^2+8x+4)=0

Use Factoring method.

(x-2)(3x^2+6x+2x+4)=0

(x-2)(3x(x+2)+2(x+2)=0

(x-2)(3x+2)(x+2)=0

Equate each factor equal to zero by using zero product property.

So the zeros of the given equation are 2, -2 and -0.667.

To find the y-intercept of the graph, put x=0.

f(0)=3(0)^3+2(0)^2-12(0)-8

f(0)=-8

So the y-intercept of the graph is f(0) = -8.

Since the higher degree is 3 , which is odd and the coefficient of higher degree is positive, therefore the ead behavior is defined as,

f(x)\rightarrow \infty \text{ as }\rightarrow \infty\\f(x)\rightarrow -\infty \text{ as }\rightarrow -\infty

It means as x decreases unboundedly then the function decreases unboundedly. similarly x increases unboundedly then the function increases unboundedly.

5 0
4 years ago
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