Cot(-30)+tan(600)-csc(-450)
1 answer:
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The complete question is missing, so i have attached it
Answer:
A) Reject the null hypothesis
B) Reject the null hypothesis
C) Fail to reject the null hypothesis
D) Reject the null hypothesis
Step-by-step explanation:
A) We are given;
Ha: μ > μ_o (This is thus, a one-tail problem)
n = 11
T = 1.91
Using online p-value from t-score calculator as attached with a DF = n - 1 = 11 - 1 = 10, and t-value = 1.91, and significance level of 0.05, and 1 tail, we have;
The p-value is 0.042602
P-value is less than significance level, thus, we will reject the null hypothesis
B) We are given;
Ha: μ < μ_o (This is thus, a one-tail problem)
n = 17
T = -3.45
Using online p-value from t-score calculator as attached with a DF = n - 1 = 17 - 1 = 16, and t-value = 1.91, and significance level of 0.05, and 1 tail, we have;
The p-value is 0.001647
P-value is less than significance level, thus, we will reject the null hypothesis
C)We are given;
Ha: μ ≠ μ_o (This is thus, a two-tail problem)
n = 7
T = 0.83
Using online p-value from t-score calculator as attached with a DF = n - 1 = 7 - 1 = 6, and t-value = 0.83, and significance level of 0.05, and 2 tail, we have;
The p-value is 0.438308.
P-value is higher than the significance level, thus, we will fail to reject the null hypothesis.
D) We are given;
Ha: μ > μ_o (This is thus, a one-tail problem)
n = 28
T = 2.13
Using online p-value from t-score calculator as attached with a DF = n - 1 = 28 - 1 = 27, and t-value = 2.13, and significance level of 0.05, and 1 tail, we have;
The p-value is 0.021218
P-value is lower than the significance level, thus, we will reject the null hypothesis
P-value is lower than the significance level, thus, we will reject the null hypothesis.
