FULL ANSWER<span>Factored form may be a product of greatest common factors or the difference of squares. For instance, the factored form of x^3 + 2x^2 - 6 = x(x+2)(x-3) and the factored form of x^2 - 16 = (x+4)(x-4)It is possible to solve for x by using factored form; x^2 + 5x + 6 can be reduced to its factored form by removing the x as a common factor. This results in (x+2)(x+3). Once in the factored form, solve for x by multiplying to get zero. In the equation (x+2)(x+3) = 0, the zero factor property explains that anything multiplied by zero equals zero. This means x + 2 = 0 and x + 3 = 0. The solutions to this formula would be x = -2 and x = -3.Once the solutions for x are found, check to make sure they work. In the equation x^2 + 5x + 6 = 0, it was found that x = -2, -3. Replace x in the equation with each of the solution values. So, [-2]^2 + 5(-2) + 6 = 0 turns into 4 - 10 + 6 = 0, which is correct, and [-3]^2 + 5(-3) + 6 = 0 becomes 9 - 15 + 6 = 0, which is also correct.
i hope this will help u w/ your question</span>
Use the equation:
76 * .8 + 61 * .2 = Final Grade
Answer:
Step-by-step explanation:
As with any equation involving fractions, you can multiply the equation by the least common denominator to eliminate fractions. Then solve in the usual way.
c) 1/a +b = c
1 +ab = ac . . . . multiply by a
1 = ac -ab . . . . subtract ab
1 = a(c -b) . . . . . factor out a
1/(c -b) = a . . . . divide by the coefficient of a
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d) (a-b)/(b-a) = 1
a -b = b -a . . . . . multiply by b-a
2a = 2b . . . . . . . . add a+b
a = b . . . . . . . . . . divide by the coefficient of a
Please be aware that this makes the original equation become 0/0 = 1. This is why a=b is not an allowed condition for this equation. As written, it reduces to -1 = 1, which is false. One could say <em>there is no solution</em>.
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f) bc +ac = ab . . . . . multiply by abc
bc = ab -ac . . . . . . subtract ac
bc = a(b -c) . . . . . . factor out a
bc/(b -c) = a . . . . . . divide by the coefficient of a
Step-by-step explanation:
3 - 2(b - 2) = 2 - 7b
To solve this first distribute -2 to (b - 2)
3 + (-2b + (-2) x -2) = 2 - 7b
when we simplify this it becomes:
3 + (-2b + 4) = 2 - 7b
We take (-2b + 4) out of the parenthesis:
3 - 2b + 4 = 2 - 7b
Now simplify again.
7 - 2b = 2 - 7b
Now send all the b's to one side and constants on the other.
7 - 2 = -7b +2b
5 = 5b
b = 1
Answer:
(-4, 0) U (1, ∞)
Step-by-step explanation:
Set each factor EQUAL to zero to find the zeroes (since it is not actually equal to zero, you will use an open circle when graphing and an open bracket when writing in interval notation).
x = 0 x-1 = 0 x + 4 = 0
x = 1 x = -4
Next, choose a value to the far left, between each of the zeroes, and to the far right to evaluate if it makes a true statement when input into the given inequality.
far left (I choose -5): -5(-5 - 1)(-5 + 4) > 0 → (-)(-)(-) > 0 → negative > 0 FALSE
- 4 to 0 (I choose -2): -2(-2 - 1)(-2 + 4) > 0 → (-)(-)(+) > 0 → positive > 0 TRUE
0 to 1 (I choose 0.5): .5(.5 - 1)(.5 + 4) > 0 → (+)(-)(+) > 0 → negative > 0 FALSE
far right (I choose 2): 2(2 - 1)(2 + 4) > 0 → (+)(+)(+) > 0 → positive > 0 TRUE
