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elena55 [62]
3 years ago
10

Mark reads 42 pages of a book every 3/4 hour. Write an equation that models the relationships between x, the number of hours Mar

k reads, and , y the number of pages of the book he reads.
Mathematics
1 answer:
Illusion [34]3 years ago
7 0

Answer:

The equation that models the relationships between x, the number of hours Mark reads, and , y the number of pages of the book he reads is:

y=56x

Step-by-step explanation:

Given:

Mark reads 42 pages every \frac{3}{4} hour.

The number of hours is given by = x

The number of pages is given by =y

The equation can be modeled as:

y=mx+b

where m represents rate of change and b represents the y-intercept or the initial value.

Rate of change ==\frac{Change\ in\ y}{Change\ in\ x}=\frac{42}{\frac{3}{4}}=42\times \frac{4}{3}=56

The initial value b=0 as Mark starts reading from 0.

So, the equation is:

y=56x

You might be interested in
you have $15,000 to invest for 5 years at 5.5% annual interest rate that is compounded continuously. how much money will you hav
MissTica

Answer:

$19,747.96

Step-by-step explanation:

You are going to want to use the continuous compound interest formula, which is shown below:

A = Pe^{rt}

<em>A = total</em>

<em>P = principal amount</em>

<em>r = interest rate (decimal)</em>

<em>t = time (years)</em>

<em />

First, lets change 5.5% into a decimal:

5.5% -> \frac{5.5}{100} -> 0.055

Next, plug in the values into the equation:

A=15,000e^{0.055(5)}

A=19,747.96

After 5 years, you will have $19,747.96

4 0
3 years ago
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
I will mark either the best or the first answer brainliest.
posledela

Answer:

11.x=16 12.x=37

Step-by-step explanation:

11.

20^2-12^2=x^2

256=x^2

x=√256

x=16

12.

13^2-5^2=y^2

144=y^2

y=12

/

y^2+35^2=x^2

12^2+35^2=x^2

1369=x^2

x=37

5 0
3 years ago
Read 2 more answers
Elizabeth spends $12.40 on a new CD. This amount is 62% of her monthly allowance. Find the amount of Elizabeth's monthly allowan
valkas [14]

Answer:

20.00

Step-by-step explanation:

6 0
3 years ago
Show work and factor ?
kvasek [131]
5\cdot\dfrac{x^2-2x}{6}:\dfrac{3x-6}{x}=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3x-6}\\\\=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3(x-2)}=\dfrac{5\cdot x\cdot x}{6\cdot3}=\dfrac{5x^2}{18}
4 0
3 years ago
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