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ASHA 777 [7]
3 years ago
13

What is the value of X is this problem? 2x+19

Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0
Since we need to find x, we need to move 19 to the other side:

2x + 19 = 0
-19 -19

Which turns into:

2x = -19

Now, we need to divide each side by 2 in order to leave x by itself:

2x = -19
—— ——
2 2

Which will get us:

x = -9.5

And that will be your answer. (Not sure if it’s correct, but I tried lol)
VashaNatasha [74]3 years ago
3 0

Answer:

6

Step-by-step explanation:

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Under normal conditions, 1.5 feet of snow will melt into 2 inches of water. During a winter season high in the mountains, 49 fee
iren [92.7K]

Answer:

Step-by-step explanation:

65.333332

4 0
2 years ago
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How many lines of symmetry does this rectangle have?<br> A. 1<br> B. 2<br> C. 3<br> D. 4<br> E. 5
Alex_Xolod [135]

Answer:

A rectangle has 4 sides with C: Two Lines of Symmetry.

Step-by-step explanation:

4 0
3 years ago
A scale drawing of a school bus has a scale of 12 inch to 5 feet. If the length of the school bus is 412 inches on the scale dra
Thepotemich [5.8K]

Answer:

actual length = 171.67 ft.

Step-by-step explanation:

scale of school bus drawing is 12 in. to 5 ft.

if the length of a school bus drawing is 412 in.

                                                     5 ft

the actual length is    = 412 in x --------

                                                     12 in

actual length = 171.67 ft.

7 0
3 years ago
Find the equation of the parabola that passes through
valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}

well, from the 1st  equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b

well, now let's plug that "b" into our 3rd equation and solve for "a".

\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill

3 0
3 years ago
Please answer asap!!!
Scilla [17]

Answer:

z = 66

Step-by-step explanation:

RS = z

QT = z - 33

Based on the midsegment theorem, QT = ½(RS)

Plug in the values

z - 33 = ½(z)

Multiply both sides by 2

2(z - 33) = z

2z - 66 = z

Add 66 to both sides

2z = z + 66

Subtract z from both sides

2z - z = 66

z = 66

8 0
3 years ago
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