A. Vertical stretch of 1/4 hortionzal stretch to a period of 2pi , phase shift of pi/6 units to the left
The value of x is 11
Because both the angles should be equal
Answer:
A. Miguel has the greatest spread.
The range of the two persons can be determined by:
Adam's range = 106 -91
= 15
Miguel's range = 105 -86
= 19
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Adam has the least spread
C. Miguel is inconsistent with the time set for training compared to that of Adam.
The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.
Answer:
D
Step-by-step explanation:
The average can be found by dividing the number of pieces (or trucks in this case) by the total, so 3204/8=400.5 pounds, or D as our answer
