First, we determine the volumes of the posts may it be cylindrical in shape or rectangular prism.
(A) cylindrical:
( π(26.7/100)² - π(24.2/100)²)*(7.5) = 0.3 m³
(B) rectangular prism:
(40/100)²(7.5) - (35/100)²(7.5) = 0.28125 m³
Then, we calculate for the amount of substance
(A) cylindrical: (0.3 m³)(2700 kg/m³) = 810 kg
(B) rectangular prism : (0.28125 m³)(2700 kg/m³) = 759.375 kg
Then, calculate for the costs
(A) (810 kg)($0.38/kg) = $307.8
(B) (759.375 kg)($0.38/kg) = $288.56
Thus, the answer for A is rectangular post
B. About $19.24 can be saved.
Answer:
|3-8|-(12/3+1)2
=|-5|-(4+1)2
=5-5x2
=5-10
=-5
You said simplify, but it can be solve.
Parallel is the answer
Perpendicular and intersecting lines both have and intersection point
Skew lines don't interest but they are not coplanar
X+y = 2
(2*2 + 2*2)
(4 + 2*2)
(4 + 4)
= 8
