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V125BC [204]
3 years ago
14

To find mileage, or how many miles a car can travel per gallon of gasoline, you can use the expression m/g, where m is the dista

nce in miles and g is the number of gallons of gas used. Find the gas mileage in miles per gallon for a car that travels 212 miles on 8 gallons of gas.
Mathematics
1 answer:
White raven [17]3 years ago
5 0
I think the answer is 26.5 mpg. I divided 212 by 8 and got 26.5 as my answer.
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the observations 7,15,x-1,x+1,24,28 have been arranged in ascending order. if the median of the data is 21. find the value of X.
marissa [1.9K]

Answer:

x = 21

Step-by-step explanation:

The following data were obtained from the question:

Set of data => 7, 15, x–1, x+1, 24, 28

Median = 21

x =?

Median is simply defined as the middle term of a given data arranged either in ascending or descending order.

Next, we shall determine the median of the set of data. This can be obtained as follow:

7, 15, x–1, x+1, 24, 28

Median = [(x–1) + (x+1)]/ 2

Finally, we shall determine the value of x as follow:

Median = [(x-1) + (x+1)]/ 2

Median = 21

21 = [(x-1) + (x+1)]/ 2

21 = [x – 1 + x + 1] /2

21 = [x + x – 1 + 1] /2

21 = 2x / 2

21 = x

Thus, x is 21

****Check****

Median = 21

x = 21

Median = [(x–1) + (x+1)] / 2

21 = [(21 – 1) + (21 + 1)] / 2

21 = [20 + 22] / 2

21 = 42/2

21 = 21

7 0
3 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
4 years ago
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