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3 years ago

What is 36 divided by 86.4?

Mathematics

2 answers:

gladu [14]3 years ago

4 0

0.41666666666 is 36 divided by 86.4

leva [86]3 years ago

4 0

The outcome is 0.42 ( after rounding off)

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A square room of volume 900 m’has a door of

Delicious77 [7]

1687.5/7.5

=225

225×12.5

=2812.5

5 0

3 years ago

Geometry Homework Question

mash [69]

Answer:

Distance is 8.485

Midpoint is (3,4)

Step-by-step explanation:

Use the points (-1,7) and (5,1)

Insert them into the equation and solve for D

$D=\sqrt{x} ((5-(-1))^2 + (1-7)^2)\\D=\sqrt{x} ((6)^2 + (-6)^2)\\D=\sqrt{x} (36+36)\\D=\sqrt{x} (72)\\D=8.485$

Insert points into second equation to find midpoint

$(\frac{_1+5}{2} , \frac{7+1}{2}) \\(\frac{6}{2} ,\frac{8}{2} )\\(3,4)$

7 0

3 years ago

Assume that trees are subjected to different levels of carbon dioxide atmosphere with 7% of the trees in a minimal growth condit

taurus [48]

Answer: The mean and standard deviation are 567.2 and 89.88 resp.

Step-by-step explanation:

Since we have given that

For 370 parts per million = 7% = 0.07

For 440 parts per million = 10% = 0.10

For 550 parts per million = 49% = 0.49

For 670 parts per million = 34% = 0.34

So, Mean of the carbon dioxide atmosphere for these trees would be

$E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2$

And

$E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794$

So, Variance would be

$Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16$

So, the standard deviation would be

$\sigma=\sqrt{8078.16}=89.88$

Hence, the mean and standard deviation are 567.2 and 89.88 resp.

3 0

4 years ago

What is the range of the function y = -x2 + 1?

meriva

<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
</span>

3 0

3 years ago

Can you please help with this.

nlexa [21]

Think it is A my dude

7 0

3 years ago

Read 2 more answers