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3 years ago

15

Solve the problems 11-4 times

1 answer:

NNADVOKAT [17]3 years ago

8 0

Answer:

12 45 67 88 90

Step-by-step explanation:

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Consider H0: μ = 45 versus H1: μ < 45. A random sample of 25 observations produced a sample mean of 41.8. Using α = .025 and

a_sh-v [17]

Given
$H0: \ \mu=45 \\ \\ H1: \ \mu\ \textless \ 45$
This is a one-tailed test.

$z= \frac{41.8-45}{6/ \sqrt{25} } = \frac{-3.2}{6/5} = \frac{-3.2}{1.2} =-2.6667$

$P(z\ \textless \ -2.6667)=0.00383$

Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.

5 0

3 years ago

Last week the office used boxes of paper. This week they used boxes of paper. How many more boxes did they use last week than th

stealth61 [152]

Answer:

Nope no help. :d

Step-by-step explanation:

8 0

3 years ago

In a random sample of 30 people who rode a roller coaster one day, the mean wait time is 46.7 minutes with a standard deviation

Rainbow [258]

Answer: C. $(29,\ 37.8)$

Step-by-step explanation:

The confidence interval for difference of two population mean is given by :-

$\overline{x}_1-\overline{x}_2\pm z_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}$

Given : Level of significance : $1-\alpha:0.99$

Then , significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=2.576$

$n_1=30\ ;\ n_2=50\\\\\overline{x}_1=46.7\ ;\ \overline{x}_2=13.3\\\\s_1=9.2\ ;\ s_2=1.9$

$46.7-13.3\pm(2.576)\sqrt{\dfrac{9.2^2}{30}+\dfrac{1.9^2}{50}}\approx33.4\pm4.38=(29.02\ ,37.78)\approx(29,\ 37.8)$

Hence, a 99% confidence interval for the difference between the mean wait times of everyone who rode both rides $(29,\ 37.8)$

5 0

3 years ago

The length of a rectangle is 2 more than twice the width. The area of the

vlada-n [284]

Answer: w=5 , L= 2+2(5)=12

Step-by-step explanation:

L=2+2W

A= 60

LxW=60, now we will replace the L

(2+2W)(W)=60 we multiply

2w^2+2w=60

2w^2+2w-60=0 we divide by 2 the equation so we can work easier

w^2+w-30=0

find out w using the quadratic equation

we will get 2 solution,

w=5 and another solution is -6, which is not valid, as the side can not be negative

8 0

2 years ago

Find the length of side BC. Round your answer to the nearest tenth.

Arturiano [62]

Answer:

2.5

Step-by-step explanation:

(6)cos(65)

7 0

2 years ago