Answer:
(y + z)(y + 4z)
Step-by-step explanation:
Instructions: Drag each tile to the correct location on the algebraic problem. Not all tiles will be used.
2 answers:
The steps involving properties of equality are shown in painful detail.
For Step 4, you add 7 to both sides of the equation (with the goal of cancelling the -7 on the left). So you have
6x -7 +7 = 12 +7 . . . . . . . showing 7 added to both sides
In the next step, this is simplified to the way you might have written it to start with:
6x = 19
There should be no confusion in any of this. All solutions of all equations make use of the properties of equality like this. Addition is used to cancel subtraction, division is used to cancel multiplication. (Root-taking cancels powers, and vice-versa; inverse trig functions cancel trig functions; and so on.)
For Step 4, you add 7 to both sides of the equation (with the goal of cancelling the -7 on the left). So you have
6x -7 +7 = 12 +7 . . . . . . . showing 7 added to both sides
In the next step, this is simplified to the way you might have written it to start with:
6x = 19
There should be no confusion in any of this. All solutions of all equations make use of the properties of equality like this. Addition is used to cancel subtraction, division is used to cancel multiplication. (Root-taking cancels powers, and vice-versa; inverse trig functions cancel trig functions; and so on.)
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The distance BC from Tower 2 to the plane will be 14,065.5 ft and the height of the plane from the ground will be 5,720.9 ft.
<h3>What is a right-angle triangle?</h3>It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.
A plane is located at C on the diagram.
There are two towers located at A and B.
The distance between the towers is 7600 feet and angles of elevation are given.
Then in the right-angle triangle ΔADC, we have
...1
Then in the right-angle triangle ΔBDC, we have
...2
From equations 1 and 2, we have
0.4452X = 0.2756 X + 2179.2649
0.1696X = 2179.2649
X = 12849.439 ≅ 12,849.4 ft
Then the distance BC from Tower 2 to the plane will be
Then the height of the plane from the ground will be
The figure is shown below.
More about the right-angle triangle link is given below.
#SPJ1
