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Akimi4 [234]
3 years ago
11

The asymptote function f(x)=3^x+4 is y=

Mathematics
1 answer:
swat323 years ago
7 0

The asymptote of the function f(x)=3^x is y = 0.

The asymptote of the function f(x)=3^x+4 is y = 0+4=4

Answer: y = 4

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Scoateti factori de sub radical, apoi calculati:<br><br> v3 + 2v27 - v75
Temka [501]
I’m not sure if your asking help to factor the equation. Here is the answer to the equation that I factored. -v^3(v^72-2v^24 + 1) Hope that helps you.
5 0
3 years ago
A taxi driver had 27 fares to and from the airport last Monday. The price for a ride to the airport is $14, and the price for a
OLga [1]

Answer:

(15, 12)

Step-by-step explanation:

Let's generate two systems of equations that fit this scenario.

Number of trips to the airport = x

Number of trips from the airport = y

Total number of trips to and from the airport = 27

Thus:

x + y = 27 => equation 1.

Total price for trips to the Airport = 14*x = 14x

Total price of trips from the airport = 7*y = 7y

Total collected for the day = $294

Thus:

14x + 7y = 294 => equation 2.

Multiply equation 1 by 7, and multiply equation 2 by 1 to make both equations equivalent.

7 × x + y = 27

1 × 14x + 7y = 294

Thus:

7x + 7y = 189 => equation 3

14x + 7y = 294 => equation 4

Subtract equation 4 from equation 3

-7x = -105

Divide both sides by -7

x = 15

Substitute x = 15 in equation 1

x + y = 27

15 + y = 27

Subtract both sides by 15

y = 27 - 15

y = 12

The ordered pair would be (15, 12)

7 0
3 years ago
What is the volume of a cylinder with height 4 and radius 2? Use 3.14 for pi.
Over [174]

Answer:

50.27

v=3.14 (2 squared) 4

5 0
3 years ago
Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

4 0
3 years ago
Need help with problems 16 and 17, please? I'll do brainiac
natali 33 [55]

Answer: 16) y=-0.5x+3 and 17) y=2x-3

Step-by-step explanation:

16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Since y=3 at x=0, the y-intercept is (0,3), and b=3.

Slope=\frac{y_{2} -y_{1} }{x_{2}-x_{1}  } where (x_{1} ,y_{1}) and (x_{2} ,y_{2}) are two points on the line. Choose (0,3) and (2,2):

Slope=\frac{2-3}{2-0}=-0.5

Plug m=-0.5 and b=3 into y=mx+b:

y=-0.5x+3

17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.

Slope=\frac{y_{2} -y_{1} }{x_{2}-x_{1}  } where (x_{1} ,y_{1}) and (x_{2} ,y_{2}) are two points on the line. Choose (0,-3) and (1,-1):

Slope=\frac{-3-(-1)}{0-1}=\frac{-2}{-1}=2

Plug m=2 and b=-3 into y=mx+b:

y=2x-3

5 0
3 years ago
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