Answer:
AC = 13.38 miles
BC = 12.65 miles
Where C is the fire location
Step-by-step explanation:
Two fire-lookout stations A and B are 14 miles apart.
The bearing of the fire from station A is Upper N 35 degrees E .
This implies that angle A = 90-35= 55°( reason because B is directly NE of A)
bearing of the fire from station B is N 30 degrees W.
This signifies that angle B is 90-30 =60°
Let's call the fire position C
Angle C = 180-60-55
Angle C= 65°
For Side AC
AB/sin C = AC/sin B
14/sin 65 = AC/sin 60
AC = 13.38 miles
For Side BC
BC/sin A = AB/sin C
BC = sin 55 * (14/sin 65)
BC = 12.65 miles
Step-by-step explanation:
Let b is breadth and l is length of the cuboid such that,
Length, l = 3b and l = 2h
or
h = l/2
We know that, the volume of a cuboid box is given by :
V = lbh
Put all the values,
Breadth, b = 16.5/3 = 5.5 cm
Height, h = 16.5/2 = 8.25 cm
Hence, this is the required solution.
4(x-7) is what i got for my answer
The instructions are cut off, but if segment PQ bisects angle SQR, then you are correct in saying that angle 1 and angle 2 are congruent to one another.
