First of all, these two angles are corresponding angles, which means that they equal each other. So, the equation here would be: 2x+18= 4x-14.

Step 1- Move the variables to one side.

2x+18= 4x-14

-2x -2x

18= 2x-14

Step 2- Add 14 to both sides of the equation.

18= 2x-14

+14 +14

32= 2x

Step 3- Divide 2 to both sides of the equation to isolate the variable.

32= 2x

2 2

x= 16

7 0

3 years ago

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Limit xtens to 0 x^2logx^2 what is the ans of interminate forms?

GarryVolchara [31]

Rewrite the limit as

$\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}$

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

$\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}$

7 0

3 years ago