Step-by-step explanation:
2/3 lost is 1/3 kept
2/3 of the 1/3 kept is 2/9 lost
1/3 x - 2/9 x = 4
3/9 x - 2/9 x = 4
1/9 x = 4
x = 36
First she lost 2/3 of 36, which is 24. She had 12 left. Then she lost 2/3 of 12 which is 8. She had 4 left.
Answer:
C. 
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Trig Derivatives
Logarithmic Derivatives
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Product Rule]:
![\displaystyle f'(x) = \frac{d}{dx}[ln(x)]cos(x) + ln(x)\frac{d}{dx}[cos(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bln%28x%29%5Dcos%28x%29%20%2B%20ln%28x%29%5Cfrac%7Bd%7D%7Bdx%7D%5Bcos%28x%29%5D)
- Logarithmic Derivative:
![\displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)\frac{d}{dx}[cos(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx%7Dcos%28x%29%20%2B%20ln%28x%29%5Cfrac%7Bd%7D%7Bdx%7D%5Bcos%28x%29%5D)
- Trig Derivative:
![\displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)[-sin(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx%7Dcos%28x%29%20%2B%20ln%28x%29%5B-sin%28x%29%5D)
- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Book: College Calculus 10e
Answer:
Its A i just took the test
Step-by-step explanation:
Answer:
6 * 10^2
Step-by-step explanation:
Simplify : (4.2×10^7)÷(7×10^4)
(4.2 × 10^7) / (7 × 10^4)
From indices : 10^a ÷ 10^b = 10^(a - b)
(4.2 / 7) * 10^(7-4)
0.6 * 10^3
= 6 * 10^2
Hence, (4.2×10^7)÷(7×10^4) = 6 * 10^2
Answer:
A) 
Step-by-step explanation:
The graph has x-intercepts at
and
, so our factors for the polynomial will be
and
. This means we can rule out options B and D.
Our graph also has a y-intercept of
when
, so if we let
and
, we can find the multiplier:

Thus, the correct equation is A) 