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3 years ago

9

A data set that consists of many values can be summarized using the five-number summary. Arrange these five values in order from

least to greatest. median maximum minimum Q1 Q3

1 answer:

Bess [88]3 years ago

8 0

The IQR is q1-q3! Put the numbers in order, least to greatest. then find the quartiles.

You might be interested in

#3 pls????????????????

zvonat [6]

Answer:

ΔGFE≈ΔJKL

Step-by-step explanation:

5 0

3 years ago

X is number of 1$ bills 1/2x =20

SOVA2 [1]

If your trying to solve for x it’s 40, x=40
2 times 1/2x =2x20
x=2x20
x=40

4 0

3 years ago

Explain how the zero property in the problem 2/3 (0) = 0 (2/3) = 0 is the same with any rational number.

Gala2k [10]

Its because the power of zero is undefined

6 0

3 years ago

Hunter-Best [27]

Answer:

There is a 1/8 chance.

If there are 4 cards in the deck, and one three card, it makes it a 1/4 chance of picking the card the first time.

The probability stays the second time you pull out a card.

So, you would do the equation 1/4 * 1/4, which is 1/8. That is the answer.

4 0

3 years ago

It is possible to get 2 solutions when the system of equations is: (check all that apply)

SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as $x^2+ y^2 = 1$ ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

$x^2 + x^2 = 1\\2x^2 = 1\\$

$x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$ so Y = $+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$

so the two solution are ( $(\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }$ )

A system of the equation of a parabola and a linear equation

Let equation of Parabola be $y^2 = x$

and linear equation y = x

substitute

$x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1$

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0

3 years ago